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A student says, “1.732 is a terminating decimal and is very close to \(\sqrt{3}\), so \(\sqrt{3}\) is rational.” What is the main error in the argument?

Answer and explanation

Correct answer: Treating an approximation as exactly equal to the actual number

1.732 is only an approximation, not the exact value of \(\sqrt{3}\). Check: \((1.732)^2=2.999824\ne3\). In exams, never treat a close decimal approximation as an equality.

Related tags

Number SystemsIrrational NumbersSquare Root 3MisconceptionsDecimal ApproximationClass 9 MathematicsProof Of Irrationality Of Square Root 2 And Square Root 3Mathematics

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