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A square has an area of \(2\text{ cm}^2\). A student says, “Since the area is rational, the side of the square must also be rational.” What is the correct correction to this statement?

Answer and explanation

Correct answer: The side is \(\sqrt{2}\text{ cm}\) and is irrational; a rational area does not necessarily give a rational side.

For side \(s\), \(s^2=2\), so \(s=\sqrt{2}\). If \(\sqrt{2}=a/b\) is in lowest terms, \(a^2=2b^2\) makes both \(a\) and \(b\) even, giving a contradiction. Exam tip: a rational area need not give a rational side.

Related tags

Number SystemsIrrational NumbersSquare Root 2Proof By ContradictionGeometry ApplicationProof Of Irrationality Of Square Root 2 And Square Root 3MathematicsClass 9 Mcq

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