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A calculator displays \(\sqrt{3}\) as 1.732. Mohan concludes that \(\sqrt{3}\) is rational. What is Mohan’s error?

Answer and explanation

Correct answer: A calculator shows only an approximate decimal value; 1.732 is not the exact value of \(\sqrt{3}\).

A calculator gives a rounded approximation, so 1.732 is not the exact value of \(\sqrt{3}\). For proof, assume \(\sqrt{3}=a/b\) in lowest terms and derive a contradiction. Exam tip: never use a displayed decimal as proof of rationality.

Related tags

Number SystemsIrrational NumbersSquare Root 3Proof By ContradictionMisconceptionsProof Of Irrationality Of Square Root 2 And Square Root 3MathematicsClass 9 Mcq

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