If two chords of a circle are equal in length, then how are their distances from the centre?
In a circle, chords of equal length are at equal perpendicular distances from the centre. A perpendicular drawn from the centre to each chord bisects that chord. Since the chords are equal and the radii are equal, the resulting right triangles are congruent; hence their distances from the centre are equal. Options B and C are incorrect because they imply unequal distances. Exam tip: The converse is also true: chords equidistant from the centre are equal.
View question details