यदि \(f:R\to R\), (f(x)=|x|+2), तो परास क्या होगा?
If \(f:R\to R\), (f(x)=|x|+2), what is the range?
Explanation opens after your attempt
A. \([2,\infty\))
Concept
\(|x|\ge0\) for every real (x).
Why this answer is correct
Therefore \(|x|+2\ge2\).
Exam Tip
At (x=0), the minimum value (2) is obtained, so the range is \([2,\infty\)). चरण 1: \(|x|\ge0\) हर वास्तविक (x) के लिए। चरण 2: इसलिए \(|x|+2\ge2\)। चरण 3: (x=0) पर न्यूनतम मान (2) मिलता है, अतः परास \([2,\infty\)) है।
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