यदि \(f:R\to R\), (f(x)=|x|+2), तो परास क्या होगा?

If \(f:R\to R\), (f(x)=|x|+2), what is the range?

Explanation opens after your attempt
Correct Answer

A. \([2,\infty\))

Step 1

Concept

\(|x|\ge0\) for every real (x).

Step 2

Why this answer is correct

Therefore \(|x|+2\ge2\).

Step 3

Exam Tip

At (x=0), the minimum value (2) is obtained, so the range is \([2,\infty\)). चरण 1: \(|x|\ge0\) हर वास्तविक (x) के लिए। चरण 2: इसलिए \(|x|+2\ge2\)। चरण 3: (x=0) पर न्यूनतम मान (2) मिलता है, अतः परास \([2,\infty\)) है।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(f:R\to R\), (f(x)=|x|+2), तो परास क्या होगा? / If \(f:R\to R\), (f(x)=|x|+2), what is the range?

Correct Answer: A. \([2,\infty\)). Explanation: चरण 1: \(|x|\ge0\) हर वास्तविक (x) के लिए। चरण 2: इसलिए \(|x|+2\ge2\)। चरण 3: (x=0) पर न्यूनतम मान (2) मिलता है, अतः परास \([2,\infty\)) है। / Step 1: \(|x|\ge0\) for every real (x). Step 2: Therefore \(|x|+2\ge2\). Step 3: At (x=0), the minimum value (2) is obtained, so the range is \([2,\infty\)).

Which concept should I revise for this Mathematics MCQ?

\(|x|\ge0\) for every real (x).

What exam hint can help solve this Mathematics question?

At (x=0), the minimum value (2) is obtained, so the range is \([2,\infty\)). चरण 1: \(|x|\ge0\) हर वास्तविक (x) के लिए। चरण 2: इसलिए \(|x|+2\ge2\)। चरण 3: (x=0) पर न्यूनतम मान (2) मिलता है, अतः परास \([2,\infty\)) है।