यदि \(f:\mathbb{R}\to\mathbb{R}\) और (f(x)=\cos x) है, तो (f) एकैकी नहीं है क्योंकि
If \(f:\mathbb{R}\to\mathbb{R}\) and (f(x)=\cos x), (f) is not one-one because
Explanation opens after your attempt
A. (f(0)=f\(2\pi\)) और \(0\neq 2\pi\)(f(0)=f\(2\pi\)) and \(0\neq 2\pi\)
Concept
\(\cos x\) is a periodic function.
Why this answer is correct
\(\cos 0=1\) and \(\cos 2\pi=1\), while \(0\neq 2\pi\).
Exam Tip
Periodic functions on all real numbers are generally not one-one. चरण 1: \(\cos x\) एक आवर्ती फलन है। चरण 2: \(\cos 0=1\) और \(\cos 2\pi=1\), जबकि \(0\neq 2\pi\)। चरण 3: आवर्ती फलन पूरे \(\mathbb{R}\) पर सामान्यतः एकैकी नहीं होते।
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