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For the function (f:[-1,\infty)\to[0,\infty)), (f(x)=x^2+2x+1), which conclusion is correct?फलन (f:[-1,\infty)\to[0,\infty)), (f(x)=x^2+2x+1) के लिए कौन-सा निष्कर्ष सही है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: It is ontoयह आच्छादक है
Step 1: (f(x)=(x+1)^2) and the domain has (x\ge -1). Step 2: Since (x+1\ge0), every (y\in[0,\infty)) is obtained. Step 3: A restricted domain can still make a function onto if it covers the whole codomain.चरण 1: (f(x)=(x+1)^2) और प्रांत में (x\ge -1) है। चरण 2: (x+1\ge0), इसलिए ((x+1)^2) से हर (y\in[0,\infty)) मिल जाता है। चरण 3: सीमित प्रांत में भी आच्छादकता संभव है, यदि पूरा सहप्रांत ढक जाए।
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