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If \(f:\left(-\frac{\pi}{2},\frac{\pi}{2}\right)\to\mathbb{R}\) and \(f(x)=\tan x\), why is (f) onto?

Answer and explanation

Correct answer: Because for every \(y\in\mathbb{R}\), \(x=\tan^{-1}y\) lies in this domain

Step 1: On the principal interval \(\left(-\frac{\pi}{2},\frac{\pi}{2}\right)\), (\tan x) covers all real numbers. Step 2: For every real (y), \(x=\tan^{-1}y\) lies in that interval. Step 3: Inverse trigonometric values help prove onto property.

Related tags

Onto FunctionTangentPrincipal IntervalPreimageRelations And FunctionsMathematicsClass 12 Mcq

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