0 reads0 ratings0 helpful
If (f:\mathbb{R}\to\mathbb{R}), (f(x)=\frac{x}{1+x^2}), why is it not onto?यदि (f:\mathbb{R}\to\mathbb{R}), (f(x)=\frac{x}{1+x^2}) है, तो यह आच्छादी क्यों नहीं है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: Because (2) is not in the rangeक्योंकि (2) परास में नहीं आता
Step 1: (\frac{x}{1+x^2}) is bounded and satisfies (-\frac{1}{2}\le f(x)\le\frac{1}{2}). Step 2: The codomain (\mathbb{R}) contains (2), but (f(x)=2) is impossible. Step 3: For rational expressions, identify range bounds.चरण 1: (\frac{x}{1+x^2}) का मान सीमित रहता है और (-\frac{1}{2}\le f(x)\le\frac{1}{2})। चरण 2: सहप्रांत (\mathbb{R}) में (2) है, पर (f(x)=2) संभव नहीं। चरण 3: भिन्नात्मक फलनों में परास की सीमा पहचानें।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
