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If (f:\mathbb{Z}\to {n\in\mathbb{Z}:n\ge0}), (f(n)=n^2), what is correct about (f)?यदि (f:\mathbb{Z}\to {n\in\mathbb{Z}:n\ge0}), (f(n)=n^2), तो (f) के बारे में क्या सही है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: Not onto because every non-negative integer is not a squareआच्छादक नहीं है क्योंकि हर अरिणात्मक पूर्णांक वर्ग नहीं होता
Step 1: (n^2) gives only perfect squares such as (0,1,4,9). Step 2: The codomain contains non-negative integers like (2) and (3), which are not perfect squares. Step 3: Even with a non-negative codomain, not every value must be obtained.चरण 1: (n^2) केवल पूर्ण वर्ग देता है जैसे (0,1,4,9)। चरण 2: सहक्षेत्र में (2) और (3) जैसे अरिणात्मक पूर्णांक हैं जो पूर्ण वर्ग नहीं हैं। चरण 3: सहक्षेत्र अरिणात्मक होने पर भी सभी मान मिलें यह जरूरी नहीं।
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