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If \(f:\left[0,\frac{\pi}{2}\right]\to [-1,1]\), \(f(x)=\sin x\), which statement is correct?

Answer and explanation

Correct answer: Not onto because negative values are not obtained

Step 1: (\sin x) goes from (0) to (1) on \(\left[0,\frac{\pi}{2}\right]\). Step 2: The codomain ([-1,1]) has negative values, which are not obtained. Step 3: The same trigonometric formula can give different answers on different intervals.

Related tags

Relations And FunctionsOnto FunctionSine IntervalMathematicsClass 12 Mcq

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