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If (f:\mathbb{R}\to(-1,1)), (f(x)=\frac{x}{\sqrt{1+x^2}}), choose the correct option.

Answer and explanation

Correct answer: Onto and one-one

Step 1: The value of this function always lies between (-1) and (1). Step 2: For any (y\in(-1,1)), (x=\frac{y}{\sqrt{1-y^2}}) is real, so every codomain element has a preimage. The function is also increasing, so it is one-one. Step 3: For fractional square-root functions, first identify the limiting range.

Related tags

Relations-FunctionsOnto-FunctionReal-FunctionOnto FunctionRelations And FunctionsMathematicsClass 12 Mcq

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