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If (f:\mathbb{R}\to[0,1)), (f(x)=\frac{x^2}{1+x^2}), which statement is correct about (f)?

Answer and explanation

Correct answer: Onto but not one-one

Step 1: The range of this function is ([0,1)). Step 2: The codomain is also ([0,1)), so the function is onto. But (f(2)=f(-2)), so it is not one-one. Step 3: With the correct codomain, the same function can become onto.

Related tags

Relations-FunctionsCodomain-AdjustmentOnto-FunctionOnto FunctionRelations And FunctionsMathematicsClass 12 Mcq

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