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Subjects
Class 12MathematicsRelations and FunctionsOnto functionMedium
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If (f:\mathbb{R}\to(0,1]), (f(x)=\frac{1}{1+x^2}), what type of function is (f)?

Answer and explanation

Correct answer: Onto but not one-one

Step 1: The range of this function is ((0,1]). Step 2: The codomain is also ((0,1]), so the function is onto. But (f(1)=f(-1)=\frac{1}{2}), so it is not one-one. Step 3: For even functions, compare values at (x) and (-x).

Related tags

Relations-FunctionsRange-As-CodomainOnto-FunctionOnto FunctionRelations And FunctionsMathematicsClass 12 Mcq
सुधार सुझाएँ / Earn

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10 more MCQs
  1. 1If (f:\mathbb{R}\to\mathbb{R}), (f(x)=x+5), which statement about (f) is correct?
  2. 2If (f:\mathbb{R}\to\mathbb{R}), (f(x)=x^2), why is (f) not onto?
  3. 3If (f:\mathbb{R}\to[0,\infty)), (f(x)=x^2), what is the correct statement about (f)?
  4. 4For sets (A={1,2,3}) and (B={a,b}), (f={(1,a),(2,b),(3,a)}). Choose the correct statement about (f:A\to B).
  5. 5For (A={1,2,3}) and (B={p,q,r}), (f={(1,p),(2,p),(3,q)}). Why is it not onto?
  6. 6If (f:\mathbb{R}\to\mathbb{R}), (f(x)=2x-7), what should (x) be for any (y\in\mathbb{R}) so that (f(x)=y)?
  7. 7If (f:\mathbb{N}\to\mathbb{N}), (f(n)=n+1), why is (f) not onto?
  8. 8If (f:\mathbb{Z}\to\mathbb{Z}), (f(n)=n-3), what is the correct statement about (f)?
  9. 9If (f:\mathbb{Z}\to\mathbb{Z}), (f(n)=2n), why is (f) not onto?
  10. 10If (f:\mathbb{R}\to(0,\infty)), (f(x)=e^x), which statement is correct?
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