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If (f:[0,\infty)\to\mathbb{R}), (f(x)=\sqrt[3]{x}), why is it not onto?यदि (f:[0,\infty)\to\mathbb{R}), (f(x)=\sqrt[3]{x}) है, तो यह आच्छादी क्यों नहीं है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: Because negative values are not obtainedक्योंकि ऋणात्मक मान नहीं मिलते
Step 1: In the domain ([0,\infty)), (x) is non-negative. Step 2: Therefore (\sqrt[3]{x}) is also non-negative, and a value like (-1) is not obtained. Step 3: The range of a cube-root function depends on its domain.चरण 1: प्रांत ([0,\infty)) में (x) अऋणात्मक है। चरण 2: इसलिए (\sqrt[3]{x}) भी अऋणात्मक होगा और (-1) जैसा मान नहीं मिलेगा। चरण 3: घनमूल का परास प्रांत पर निर्भर करता है।
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