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If (f:\mathbb{R}\to\mathbb{R}), (f(x)=\sqrt{x^2}), why is it not onto?यदि (f:\mathbb{R}\to\mathbb{R}), (f(x)=\sqrt{x^2}) है, तो यह आच्छादी क्यों नहीं है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: Because negative values are not obtainedक्योंकि ऋणात्मक मान नहीं मिलते
Step 1: (\sqrt{x^2}=|x|). Step 2: Its value is never negative, while the codomain (\mathbb{R}) contains negative values. Step 3: Compare a modulus-type range with the real codomain carefully.चरण 1: (\sqrt{x^2}=|x|) है। चरण 2: इसका मान कभी ऋणात्मक नहीं होता, जबकि सहप्रांत (\mathbb{R}) में ऋणात्मक मान हैं। चरण 3: मापांक जैसे परास को वास्तविक सहप्रांत से तुलना करें।
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