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If (f:\mathbb{R}\to(-1,1)), (f(x)=\frac{x}{\sqrt{1+x^2}}), what is the correct statement about (f)?

Answer and explanation

Correct answer: It is onto

Step 1: The value of (\frac{x}{\sqrt{1+x^2}}) lies between (-1) and (1). Step 2: Every value in the open interval ((-1,1)) can be obtained for some real (x). Step 3: In bounded ranges, check whether endpoints are included or excluded.

Related tags

Bounded FunctionOntoOpen IntervalRational RadicalOnto FunctionRelations And FunctionsMathematicsClass 12 Mcq

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