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If (f:[0,\pi]\to[-1,1]), (f(x)=\sin x), why is (f) not onto?

Answer and explanation

Correct answer: Because negative values are not obtained

Step 1: On ([0,\pi]), the range of (\sin x) is ([0,1]). Step 2: The codomain ([-1,1]) contains negative values, but they are not obtained from this domain. Step 3: For trigonometric functions, changing the domain changes onto nature.

Related tags

Sine FunctionNot OntoRestricted DomainCodomainOnto FunctionRelations And FunctionsMathematicsClass 12 Mcq

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