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If (f:\mathbb{R}\to\mathbb{R}), (f(x)=5x), then (f) is onto because which (x) gives (y)?यदि (f:\mathbb{R}\to\mathbb{R}), (f(x)=5x) है, तो (f) आच्छादी है क्योंकि किस (x) से (y) मिलेगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(x=\frac{y}{5}\) / (x=\frac{y}{5})\(x=\frac{y}{5}\) / (x=\frac{y}{5})
Step 1: Solve (5x=y). Step 2: This gives (x=\frac{y}{5}), which is real for every real (y). Step 3: A function of the form (ax) with (a\ne0) is onto on (\mathbb{R}).चरण 1: (5x=y) हल करें। चरण 2: इससे (x=\frac{y}{5}) मिलता है, जो हर वास्तविक (y) के लिए वास्तविक है। चरण 3: (ax) रूप में (a\ne0) हो तो फलन (\mathbb{R}) पर आच्छादी होता है।
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