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Subjects
Class 12MathematicsRelations and FunctionsOnto functionEasy
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If (f:\mathbb{R}\to\mathbb{R}), (f(x)=x^2), why is (f) not onto?

Answer and explanation

Correct answer: Because negative real values are not obtained

Step 1: The value of (x^2) is always (0) or positive. Step 2: The codomain (\mathbb{R}) contains negative values such as (-1), but they are not in the range. Step 3: To test onto nature, compare range with codomain.

Related tags

Square FunctionNot OntoRangeCodomainOnto FunctionRelations And FunctionsMathematicsClass 12 Mcq
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10 more MCQs
  1. 1If (f:\mathbb{R}\to\mathbb{R}), (f(x)=x+5), which statement about (f) is correct?
  2. 2If (f:\mathbb{R}\to[0,\infty)), (f(x)=x^2), what is the correct statement about (f)?
  3. 3For sets (A={1,2,3}) and (B={a,b}), (f={(1,a),(2,b),(3,a)}). Choose the correct statement about (f:A\to B).
  4. 4For (A={1,2,3}) and (B={p,q,r}), (f={(1,p),(2,p),(3,q)}). Why is it not onto?
  5. 5If (f:\mathbb{R}\to\mathbb{R}), (f(x)=2x-7), what should (x) be for any (y\in\mathbb{R}) so that (f(x)=y)?
  6. 6If (f:\mathbb{N}\to\mathbb{N}), (f(n)=n+1), why is (f) not onto?
  7. 7If (f:\mathbb{Z}\to\mathbb{Z}), (f(n)=n-3), what is the correct statement about (f)?
  8. 8If (f:\mathbb{Z}\to\mathbb{Z}), (f(n)=2n), why is (f) not onto?
  9. 9If (f:\mathbb{R}\to(0,\infty)), (f(x)=e^x), which statement is correct?
  10. 10If (f:\mathbb{R}\to\mathbb{R}), (f(x)=e^x), why is (f) not onto?
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