\(\sin^{-1}x\) की सीमा से कौन सा मान संभव नहीं है?

Which value is not possible from the range of \(\sin^{-1}x\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(\frac{2\pi}{3}\)

Step 1

Concept

The range of \(\sin^{-1}x\) is \(\left[-\frac{\pi}{2},\frac{\pi}{2}\right]\). The value \(\frac{2\pi}{3}\) lies outside this range.

Step 2

Why this answer is correct

The correct answer is A. \(\frac{2\pi}{3}\). The range of \(\sin^{-1}x\) is \(\left[-\frac{\pi}{2},\frac{\pi}{2}\right]\). The value \(\frac{2\pi}{3}\) lies outside this range.

Step 3

Exam Tip

\(\sin^{-1}x\) की सीमा \(\left[-\frac{\pi}{2},\frac{\pi}{2}\right]\) है। \(\frac{2\pi}{3}\) इस सीमा के बाहर है।

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Mathematics Answer, Explanation and Revision Hints

\(\sin^{-1}x\) की सीमा से कौन सा मान संभव नहीं है? / Which value is not possible from the range of \(\sin^{-1}x\)?

Correct Answer: A. \(\frac{2\pi}{3}\). Explanation: \(\sin^{-1}x\) की सीमा \(\left[-\frac{\pi}{2},\frac{\pi}{2}\right]\) है। \(\frac{2\pi}{3}\) इस सीमा के बाहर है। / The range of \(\sin^{-1}x\) is \(\left[-\frac{\pi}{2},\frac{\pi}{2}\right]\). The value \(\frac{2\pi}{3}\) lies outside this range.

Which concept should I revise for this Mathematics MCQ?

The range of \(\sin^{-1}x\) is \(\left[-\frac{\pi}{2},\frac{\pi}{2}\right]\). The value \(\frac{2\pi}{3}\) lies outside this range.

What exam hint can help solve this Mathematics question?

\(\sin^{-1}x\) की सीमा \(\left[-\frac{\pi}{2},\frac{\pi}{2}\right]\) है। \(\frac{2\pi}{3}\) इस सीमा के बाहर है।