(\tan^{-1}\(\tan x\)=x) कब सीधे सही माना जा सकता है?

When can (\tan^{-1}\(\tan x\)=x) be directly true?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

A. जब (x\in\left\(-\frac{\pi}{2},\frac{\pi}{2}\right\))When (x\in\left\(-\frac{\pi}{2},\frac{\pi}{2}\right\))

Step 1

Concept

The principal range of \(\tan^{-1}x\) is (\left\(-\frac{\pi}{2},\frac{\pi}{2}\right\)). Therefore that interval is the correct choice.

Step 2

Why this answer is correct

The correct answer is A. जब (x\in\left\(-\frac{\pi}{2},\frac{\pi}{2}\right\)) / When (x\in\left\(-\frac{\pi}{2},\frac{\pi}{2}\right\)). The principal range of \(\tan^{-1}x\) is (\left\(-\frac{\pi}{2},\frac{\pi}{2}\right\)). Therefore that interval is the correct choice.

Step 3

Exam Tip

\(\tan^{-1}x\) की प्रधान सीमा (\left\(-\frac{\pi}{2},\frac{\pi}{2}\right\)) है। इसलिए वही अंतराल सही चयन है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

(\tan^{-1}\(\tan x\)=x) कब सीधे सही माना जा सकता है? / When can (\tan^{-1}\(\tan x\)=x) be directly true?

Correct Answer: A. जब (x\in\left\(-\frac{\pi}{2},\frac{\pi}{2}\right\)) / When (x\in\left\(-\frac{\pi}{2},\frac{\pi}{2}\right\)). Explanation: \(\tan^{-1}x\) की प्रधान सीमा (\left\(-\frac{\pi}{2},\frac{\pi}{2}\right\)) है। इसलिए वही अंतराल सही चयन है। / The principal range of \(\tan^{-1}x\) is (\left\(-\frac{\pi}{2},\frac{\pi}{2}\right\)). Therefore that interval is the correct choice.

Which concept should I revise for this Mathematics MCQ?

The principal range of \(\tan^{-1}x\) is (\left\(-\frac{\pi}{2},\frac{\pi}{2}\right\)). Therefore that interval is the correct choice.

What exam hint can help solve this Mathematics question?

\(\tan^{-1}x\) की प्रधान सीमा (\left\(-\frac{\pi}{2},\frac{\pi}{2}\right\)) है। इसलिए वही अंतराल सही चयन है।