\(समुच्चय (C={x\in \mathbb{N}: x\) सम है और x संख्या 18 का भाजक है}) कौन-सा है?
\(Which set is (C={x\in \mathbb{N}: x\) is even and x is a divisor of 18})?
Explanation opens after your attempt
Correct Answer
A. \(C=\{2,6,18\}\)
Concept
The divisors of (18) are (1,2,3,6,9,18).
Why this answer is correct
The even divisors among them are (2,6,18). Hence \(C=\{2,6,18\}\).
Exam Tip
First list all divisors, then check evenness or oddness. चरण 1: (18) के भाजक (1,2,3,6,9,18) हैं। चरण 2: इनमें सम भाजक (2,6,18) हैं। इसलिए \(C=\{2,6,18\}\)। चरण 3: पहले सभी भाजक लिखें और फिर सम-विषम की जांच करें।
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