फलन (f(x)=\sqrt{|x|-3}) का प्रांत क्या है?

What is the domain of (f(x)=\sqrt{|x|-3})?

Explanation opens after your attempt
Correct Answer

A. ( \(-\infty,-3]\cup[3,\infty\) )

Step 1

Concept

The square root needs \(|x|-3\ge 0\). Hence \(|x|\ge 3\), so \(x\le -3\) or \(x\ge 3\).

Step 2

Why this answer is correct

The correct answer is A. ( \(-\infty,-3]\cup[3,\infty\) ). The square root needs \(|x|-3\ge 0\). Hence \(|x|\ge 3\), so \(x\le -3\) or \(x\ge 3\).

Step 3

Exam Tip

वर्गमूल के लिए \(|x|-3\ge 0\) चाहिए। इसलिए \(|x|\ge 3\), यानी \(x\le -3\) या \(x\ge 3\)।

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Mathematics Answer, Explanation and Revision Hints

फलन (f(x)=\sqrt{|x|-3}) का प्रांत क्या है? / What is the domain of (f(x)=\sqrt{|x|-3})?

Correct Answer: A. ( \(-\infty,-3]\cup[3,\infty\) ). Explanation: वर्गमूल के लिए \(|x|-3\ge 0\) चाहिए। इसलिए \(|x|\ge 3\), यानी \(x\le -3\) या \(x\ge 3\)। / The square root needs \(|x|-3\ge 0\). Hence \(|x|\ge 3\), so \(x\le -3\) or \(x\ge 3\).

Which concept should I revise for this Mathematics MCQ?

The square root needs \(|x|-3\ge 0\). Hence \(|x|\ge 3\), so \(x\le -3\) or \(x\ge 3\).

What exam hint can help solve this Mathematics question?

वर्गमूल के लिए \(|x|-3\ge 0\) चाहिए। इसलिए \(|x|\ge 3\), यानी \(x\le -3\) या \(x\ge 3\)।