फलन (f(x)=\sqrt{x-1}+\sqrt{x+2}) का प्रांत क्या है?

What is the domain of (f(x)=\sqrt{x-1}+\sqrt{x+2})?

Explanation opens after your attempt
Correct Answer

A. \( [1,\infty\) )

Step 1

Concept

Both square roots need \(x\ge 1\) and \(x\ge -2\). The stricter combined condition is \(x\ge 1\).

Step 2

Why this answer is correct

The correct answer is A. \( [1,\infty\) ). Both square roots need \(x\ge 1\) and \(x\ge -2\). The stricter combined condition is \(x\ge 1\).

Step 3

Exam Tip

दोनों वर्गमूलों के लिए \(x\ge 1\) और \(x\ge -2\) चाहिए। संयुक्त शर्त अधिक कठोर \(x\ge 1\) है।

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Mathematics Answer, Explanation and Revision Hints

फलन (f(x)=\sqrt{x-1}+\sqrt{x+2}) का प्रांत क्या है? / What is the domain of (f(x)=\sqrt{x-1}+\sqrt{x+2})?

Correct Answer: A. \( [1,\infty\) ). Explanation: दोनों वर्गमूलों के लिए \(x\ge 1\) और \(x\ge -2\) चाहिए। संयुक्त शर्त अधिक कठोर \(x\ge 1\) है। / Both square roots need \(x\ge 1\) and \(x\ge -2\). The stricter combined condition is \(x\ge 1\).

Which concept should I revise for this Mathematics MCQ?

Both square roots need \(x\ge 1\) and \(x\ge -2\). The stricter combined condition is \(x\ge 1\).

What exam hint can help solve this Mathematics question?

दोनों वर्गमूलों के लिए \(x\ge 1\) और \(x\ge -2\) चाहिए। संयुक्त शर्त अधिक कठोर \(x\ge 1\) है।