फलन (f(x)=\sqrt{\frac{x-1}{x+2}}) का प्रांत क्या है?
What is the domain of (f(x)=\sqrt{\frac{x-1}{x+2}})?
Explanation opens after your attempt
Correct Answer
A. ( \(-\infty,-2\)\cup[1,\infty) )
Concept
The expression inside the square root must satisfy \(\frac{x-1}{x+2}\ge 0\) and \(x\ne -2\). A sign chart gives (x<-2) or \(x\ge 1\).
Why this answer is correct
The correct answer is A. ( \(-\infty,-2\)\cup[1,\infty) ). The expression inside the square root must satisfy \(\frac{x-1}{x+2}\ge 0\) and \(x\ne -2\). A sign chart gives (x<-2) or \(x\ge 1\).
Exam Tip
वर्गमूल के अंदर \(\frac{x-1}{x+2}\ge 0\) और \(x\ne -2\) चाहिए। संकेत सारणी से (x<-2) या \(x\ge 1\) मिलता है।
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