फलन (f(x)=\sqrt{1-|x-2|}) का प्रांत क्या है?

What is the domain of (f(x)=\sqrt{1-|x-2|})?

Explanation opens after your attempt
Correct Answer

A. ( [1,3] )

Step 1

Concept

The square root needs \(1-|x-2|\ge 0\). Thus \(|x-2|\le 1\), so \(1\le x\le 3\).

Step 2

Why this answer is correct

The correct answer is A. ( [1,3] ). The square root needs \(1-|x-2|\ge 0\). Thus \(|x-2|\le 1\), so \(1\le x\le 3\).

Step 3

Exam Tip

वर्गमूल के लिए \(1-|x-2|\ge 0\) चाहिए। इसलिए \(|x-2|\le 1\), यानी \(1\le x\le 3\)।

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Mathematics Answer, Explanation and Revision Hints

फलन (f(x)=\sqrt{1-|x-2|}) का प्रांत क्या है? / What is the domain of (f(x)=\sqrt{1-|x-2|})?

Correct Answer: A. ( [1,3] ). Explanation: वर्गमूल के लिए \(1-|x-2|\ge 0\) चाहिए। इसलिए \(|x-2|\le 1\), यानी \(1\le x\le 3\)। / The square root needs \(1-|x-2|\ge 0\). Thus \(|x-2|\le 1\), so \(1\le x\le 3\).

Which concept should I revise for this Mathematics MCQ?

The square root needs \(1-|x-2|\ge 0\). Thus \(|x-2|\le 1\), so \(1\le x\le 3\).

What exam hint can help solve this Mathematics question?

वर्गमूल के लिए \(1-|x-2|\ge 0\) चाहिए। इसलिए \(|x-2|\le 1\), यानी \(1\le x\le 3\)।