फलन (f(x)=\frac{\sqrt{x+1}}{x-2-4}) का प्रांत क्या है?

What is the domain of (f(x)=\frac{\sqrt{x+1}}{x-2-4})?

Explanation opens after your attempt
Correct Answer

A. \( [-1,\infty\)\setminus{2} )

Step 1

Concept

The square root needs \(x\ge -1\), and the denominator needs \(x\ne \pm 2\). Since (-2) is already outside the domain, only (2) is removed.

Step 2

Why this answer is correct

The correct answer is A. \( [-1,\infty\)\setminus{2} ). The square root needs \(x\ge -1\), and the denominator needs \(x\ne \pm 2\). Since (-2) is already outside the domain, only (2) is removed.

Step 3

Exam Tip

वर्गमूल के लिए \(x\ge -1\) और हर के लिए \(x\ne \pm 2\) चाहिए। (-2) पहले से प्रांत में नहीं है, इसलिए केवल (2) हटेगा।

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Mathematics Answer, Explanation and Revision Hints

फलन (f(x)=\frac{\sqrt{x+1}}{x-2-4}) का प्रांत क्या है? / What is the domain of (f(x)=\frac{\sqrt{x+1}}{x-2-4})?

Correct Answer: A. \( [-1,\infty\)\setminus{2} ). Explanation: वर्गमूल के लिए \(x\ge -1\) और हर के लिए \(x\ne \pm 2\) चाहिए। (-2) पहले से प्रांत में नहीं है, इसलिए केवल (2) हटेगा। / The square root needs \(x\ge -1\), and the denominator needs \(x\ne \pm 2\). Since (-2) is already outside the domain, only (2) is removed.

Which concept should I revise for this Mathematics MCQ?

The square root needs \(x\ge -1\), and the denominator needs \(x\ne \pm 2\). Since (-2) is already outside the domain, only (2) is removed.

What exam hint can help solve this Mathematics question?

वर्गमूल के लिए \(x\ge -1\) और हर के लिए \(x\ne \pm 2\) चाहिए। (-2) पहले से प्रांत में नहीं है, इसलिए केवल (2) हटेगा।