फलन (f(x)=\frac{1}{|x|-2}) का प्रांत क्या है?

What is the domain of (f(x)=\frac{1}{|x|-2})?

Explanation opens after your attempt
Correct Answer

A. \( \mathbb{R}\setminus{-2,2} \)

Step 1

Concept

The denominator must not be zero, so \(|x|-2\ne 0\). This gives \(x\ne -2\) and \(x\ne 2\).

Step 2

Why this answer is correct

The correct answer is A. \( \mathbb{R}\setminus{-2,2} \). The denominator must not be zero, so \(|x|-2\ne 0\). This gives \(x\ne -2\) and \(x\ne 2\).

Step 3

Exam Tip

हर शून्य नहीं होना चाहिए, इसलिए \(|x|-2\ne 0\)। इससे \(x\ne -2\) और \(x\ne 2\) मिलता है।

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Mathematics Answer, Explanation and Revision Hints

फलन (f(x)=\frac{1}{|x|-2}) का प्रांत क्या है? / What is the domain of (f(x)=\frac{1}{|x|-2})?

Correct Answer: A. \( \mathbb{R}\setminus{-2,2} \). Explanation: हर शून्य नहीं होना चाहिए, इसलिए \(|x|-2\ne 0\)। इससे \(x\ne -2\) और \(x\ne 2\) मिलता है। / The denominator must not be zero, so \(|x|-2\ne 0\). This gives \(x\ne -2\) and \(x\ne 2\).

Which concept should I revise for this Mathematics MCQ?

The denominator must not be zero, so \(|x|-2\ne 0\). This gives \(x\ne -2\) and \(x\ne 2\).

What exam hint can help solve this Mathematics question?

हर शून्य नहीं होना चाहिए, इसलिए \(|x|-2\ne 0\)। इससे \(x\ne -2\) और \(x\ne 2\) मिलता है।