असमानताओं \(x\geq 0\), \(y\geq 0\), \(2x+y\leq 12\), \(x+3y\leq 15\) के हल-क्षेत्र के शीर्ष कौन से हैं?
What are the vertices of the solution region of \(x\geq 0\), \(y\geq 0\), \(2x+y\leq 12\), and \(x+3y\leq 15\)?
Explanation opens after your attempt
A. ((0,0)), ((6,0)), (\left\(\frac{21}{5},\frac{18}{5}\right\)), ((0,5))
Concept
The intersection of the two slant lines is (\left\(\frac{21}{5},\frac{18}{5}\right\)). Use valid intercepts on the axes to choose all polygon corners.
Why this answer is correct
The correct answer is A. ((0,0)), ((6,0)), (\left\(\frac{21}{5},\frac{18}{5}\right\)), ((0,5)). The intersection of the two slant lines is (\left\(\frac{21}{5},\frac{18}{5}\right\)). Use valid intercepts on the axes to choose all polygon corners.
Exam Tip
दोनों तिरछी रेखाओं का प्रतिच्छेद (\left\(\frac{21}{5},\frac{18}{5}\right\)) है। अक्षों पर वैध अवरोध लेकर पूरे बहुभुज के कोने चुनें।
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