द्वि-असमीका \(-2<\frac{5-2x}{3}\le 3\) को हल कीजिए।
Solve the compound inequality \(-2<\frac{5-2x}{3}\le 3\).
Explanation opens after your attempt
Correct Answer
B. \(-2\le x<\frac{11}{2}\)
Concept
From \(-6<5-2x\le 9\), we get \(-11<-2x\le 4\), so \(-2\le x<\frac{11}{2}\). In compound inequalities, division by a negative reverses the direction.
Why this answer is correct
The correct answer is B. \(-2\le x<\frac{11}{2}\). From \(-6<5-2x\le 9\), we get \(-11<-2x\le 4\), so \(-2\le x<\frac{11}{2}\). In compound inequalities, division by a negative reverses the direction.
Exam Tip
\(-6<5-2x\le 9\) से \(-11<-2x\le 4\), इसलिए \(-2\le x<\frac{11}{2}\)। परीक्षा में ऋणात्मक संख्या से भाग देने पर द्वि-असमीका की दिशा बदलती है।
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