यदि \(U=\mathbb{R}\), \(A={x:x^2-9>0}\), तो (A') क्या है?
If \(U=\mathbb{R}\), \(A={x:x^2-9>0}\), what is (A')?
Explanation opens after your attempt
Correct Answer
A. ([-3,3])
Concept
\(x^2-9>0\Rightarrow x<-3\) or (x>3). Its complement is \(-3\le x\le 3\), that is ([-3,3]).
Why this answer is correct
The correct answer is A. ([-3,3]). \(x^2-9>0\Rightarrow x<-3\) or (x>3). Its complement is \(-3\le x\le 3\), that is ([-3,3]).
Exam Tip
\(x^2-9>0\Rightarrow x<-3\) या (x>3)। इसका पूरक \(-3\le x\le 3\), यानी ([-3,3]) है।
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