यदि (f(x)=\sqrt{x+2}) और (g(x)=\frac{1}{x-1}) हैं, तो ((fg)(x)) का प्रांत क्या है?

If (f(x)=\sqrt{x+2}) and (g(x)=\frac{1}{x-1}), what is the domain of ((fg)(x))?

Explanation opens after your attempt
Correct Answer

A. \([-2,\infty\)\setminus{1})

Step 1

Concept

The square root needs \(x\ge -2\), and the denominator needs \(x\ne 1\). In a product, both conditions apply together.

Step 2

Why this answer is correct

The correct answer is A. \([-2,\infty\)\setminus{1}). The square root needs \(x\ge -2\), and the denominator needs \(x\ne 1\). In a product, both conditions apply together.

Step 3

Exam Tip

वर्गमूल के लिए \(x\ge -2\) और हर के लिए \(x\ne 1\) चाहिए। गुणन में दोनों शर्तें साथ लगती हैं।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\sqrt{x+2}) और (g(x)=\frac{1}{x-1}) हैं, तो ((fg)(x)) का प्रांत क्या है? / If (f(x)=\sqrt{x+2}) and (g(x)=\frac{1}{x-1}), what is the domain of ((fg)(x))?

Correct Answer: A. \([-2,\infty\)\setminus{1}). Explanation: वर्गमूल के लिए \(x\ge -2\) और हर के लिए \(x\ne 1\) चाहिए। गुणन में दोनों शर्तें साथ लगती हैं। / The square root needs \(x\ge -2\), and the denominator needs \(x\ne 1\). In a product, both conditions apply together.

Which concept should I revise for this Mathematics MCQ?

The square root needs \(x\ge -2\), and the denominator needs \(x\ne 1\). In a product, both conditions apply together.

What exam hint can help solve this Mathematics question?

वर्गमूल के लिए \(x\ge -2\) और हर के लिए \(x\ne 1\) चाहिए। गुणन में दोनों शर्तें साथ लगती हैं।