यदि (f(x)=\sqrt{2x-1}) और (g(x)=\sqrt{7-3x}) हैं, तो ((fg)(x)) का प्रांत क्या है?

If (f(x)=\sqrt{2x-1}) and (g(x)=\sqrt{7-3x}), what is the domain of ((fg)(x))?

Explanation opens after your attempt
Correct Answer

A. \(\left[\frac{1}{2},\frac{7}{3}\right]\)

Step 1

Concept

Both square roots require \(2x-1\ge 0\) and \(7-3x\ge 0\). Hence the domain is \(\left[\frac{1}{2},\frac{7}{3}\right]\).

Step 2

Why this answer is correct

The correct answer is A. \(\left[\frac{1}{2},\frac{7}{3}\right]\). Both square roots require \(2x-1\ge 0\) and \(7-3x\ge 0\). Hence the domain is \(\left[\frac{1}{2},\frac{7}{3}\right]\).

Step 3

Exam Tip

दोनों वर्गमूलों के लिए \(2x-1\ge 0\) और \(7-3x\ge 0\) चाहिए। इसलिए प्रांत \(\left[\frac{1}{2},\frac{7}{3}\right]\) है।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\sqrt{2x-1}) और (g(x)=\sqrt{7-3x}) हैं, तो ((fg)(x)) का प्रांत क्या है? / If (f(x)=\sqrt{2x-1}) and (g(x)=\sqrt{7-3x}), what is the domain of ((fg)(x))?

Correct Answer: A. \(\left[\frac{1}{2},\frac{7}{3}\right]\). Explanation: दोनों वर्गमूलों के लिए \(2x-1\ge 0\) और \(7-3x\ge 0\) चाहिए। इसलिए प्रांत \(\left[\frac{1}{2},\frac{7}{3}\right]\) है। / Both square roots require \(2x-1\ge 0\) and \(7-3x\ge 0\). Hence the domain is \(\left[\frac{1}{2},\frac{7}{3}\right]\).

Which concept should I revise for this Mathematics MCQ?

Both square roots require \(2x-1\ge 0\) and \(7-3x\ge 0\). Hence the domain is \(\left[\frac{1}{2},\frac{7}{3}\right]\).

What exam hint can help solve this Mathematics question?

दोनों वर्गमूलों के लिए \(2x-1\ge 0\) और \(7-3x\ge 0\) चाहिए। इसलिए प्रांत \(\left[\frac{1}{2},\frac{7}{3}\right]\) है।