यदि (f(x)=\frac{3}{2-\sqrt{x}}), तो प्रांत क्या है?

If (f(x)=\frac{3}{2-\sqrt{x}}), what is the domain?

Explanation opens after your attempt
Correct Answer

A. \( [0,\infty\)\setminus{4} )

Step 1

Concept

For \(\sqrt{x}\), \(x\ge 0\), and for the denominator, \(2-\sqrt{x}\ne 0\) is needed. Hence (x=4) is removed.

Step 2

Why this answer is correct

The correct answer is A. \( [0,\infty\)\setminus{4} ). For \(\sqrt{x}\), \(x\ge 0\), and for the denominator, \(2-\sqrt{x}\ne 0\) is needed. Hence (x=4) is removed.

Step 3

Exam Tip

\(\sqrt{x}\) के लिए \(x\ge 0\) और हर के लिए \(2-\sqrt{x}\ne 0\) चाहिए। इसलिए (x=4) हटाया जाएगा।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\frac{3}{2-\sqrt{x}}), तो प्रांत क्या है? / If (f(x)=\frac{3}{2-\sqrt{x}}), what is the domain?

Correct Answer: A. \( [0,\infty\)\setminus{4} ). Explanation: \(\sqrt{x}\) के लिए \(x\ge 0\) और हर के लिए \(2-\sqrt{x}\ne 0\) चाहिए। इसलिए (x=4) हटाया जाएगा। / For \(\sqrt{x}\), \(x\ge 0\), and for the denominator, \(2-\sqrt{x}\ne 0\) is needed. Hence (x=4) is removed.

Which concept should I revise for this Mathematics MCQ?

For \(\sqrt{x}\), \(x\ge 0\), and for the denominator, \(2-\sqrt{x}\ne 0\) is needed. Hence (x=4) is removed.

What exam hint can help solve this Mathematics question?

\(\sqrt{x}\) के लिए \(x\ge 0\) और हर के लिए \(2-\sqrt{x}\ne 0\) चाहिए। इसलिए (x=4) हटाया जाएगा।