यदि (f(x)=\frac{1}{x}) और (g(x)=x) हैं, तो ((f+g)(x)) का प्रांत और ((fg)(x)) का मान क्या है?

If (f(x)=\frac{1}{x}) and (g(x)=x), what are the domain of ((f+g)(x)) and the value of ((fg)(x))?

Explanation opens after your attempt
Correct Answer

A. \(\mathbb{R}\setminus{0}\), (1)

Step 1

Concept

The domain of (f) is \(x\ne 0\), and \(fg=\frac{1}{x}\cdot x=1\). The product may simplify, but the domain comes from the original functions.

Step 2

Why this answer is correct

The correct answer is A. \(\mathbb{R}\setminus{0}\), (1). The domain of (f) is \(x\ne 0\), and \(fg=\frac{1}{x}\cdot x=1\). The product may simplify, but the domain comes from the original functions.

Step 3

Exam Tip

(f) का प्रांत \(x\ne 0\) है और \(fg=\frac{1}{x}\cdot x=1\)। उत्पाद सरल हो सकता है, पर प्रांत मूल फलन से तय होगा।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\frac{1}{x}) और (g(x)=x) हैं, तो ((f+g)(x)) का प्रांत और ((fg)(x)) का मान क्या है? / If (f(x)=\frac{1}{x}) and (g(x)=x), what are the domain of ((f+g)(x)) and the value of ((fg)(x))?

Correct Answer: A. \(\mathbb{R}\setminus{0}\), (1). Explanation: (f) का प्रांत \(x\ne 0\) है और \(fg=\frac{1}{x}\cdot x=1\)। उत्पाद सरल हो सकता है, पर प्रांत मूल फलन से तय होगा। / The domain of (f) is \(x\ne 0\), and \(fg=\frac{1}{x}\cdot x=1\). The product may simplify, but the domain comes from the original functions.

Which concept should I revise for this Mathematics MCQ?

The domain of (f) is \(x\ne 0\), and \(fg=\frac{1}{x}\cdot x=1\). The product may simplify, but the domain comes from the original functions.

What exam hint can help solve this Mathematics question?

(f) का प्रांत \(x\ne 0\) है और \(fg=\frac{1}{x}\cdot x=1\)। उत्पाद सरल हो सकता है, पर प्रांत मूल फलन से तय होगा।