यदि \(f:\mathbb{R}\to\mathbb{R}\) को (f(x)=2x-2-8x+11) से दिया गया है, तो (f) का परिसर क्या है?
If \(f:\mathbb{R}\to\mathbb{R}\) is given by (f(x)=2x-2-8x+11), what is the range of (f)?
Explanation opens after your attempt
A. \([3,\infty\))
Concept
Since (2x-2-8x+11=2(x-2)2+3), the minimum value is (3). Complete the square to find the range.
Why this answer is correct
The correct answer is A. \([3,\infty\)). Since (2x-2-8x+11=2(x-2)2+3), the minimum value is (3). Complete the square to find the range.
Exam Tip
(2x-2-8x+11=2(x-2)2+3) है, इसलिए न्यूनतम मान (3) है। वर्ग पूरा करके परिसर निकालें।
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