यदि क्षेत्र (3x+y>6) और \(x-y\leq 2\) से बनता है, तो सही सीमा-रेखा नियम कौन-सा है?
If a region is represented by (3x+y>6) and \(x-y\leq 2\), which boundary-line rule is correct?
Explanation opens after your attempt
D. (3x+y=6) टूटी और (x-y=2) ठोस होगी(3x+y=6) dashed and (x-y=2) solid
Concept
A strict inequality (>) excludes the boundary, so its line is dashed. The inequality \(\leq\) includes the boundary, so its line is solid.
Why this answer is correct
The correct answer is D. (3x+y=6) टूटी और (x-y=2) ठोस होगी / (3x+y=6) dashed and (x-y=2) solid. A strict inequality (>) excludes the boundary, so its line is dashed. The inequality \(\leq\) includes the boundary, so its line is solid.
Exam Tip
कड़ी असमानता (>) के लिए सीमा शामिल नहीं होती, इसलिए रेखा टूटी होती है। \(\leq\) में सीमा शामिल होती है, इसलिए रेखा ठोस होती है।
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