यदि \(A\cap B\cap C=\varnothing\), (n(A)=30), (n(B)=34), (n(C)=36), (n\(A\cap B\)=8), (n\(B\cap C\)=10), (n\(C\cap A\)=6) है, तो (n\(A\cup B\cup C\)) कितना है?
If \(A\cap B\cap C=\varnothing\), (n(A)=30), (n(B)=34), (n(C)=36), (n\(A\cap B\)=8), (n\(B\cap C\)=10), (n\(C\cap A\)=6), then what is (n\(A\cup B\cup C\))?
Explanation opens after your attempt
A. (76)
Concept
The union of three sets is (30+34+36-8-10-6+0=76). If the centre is empty, keep the final addition as (0).
Why this answer is correct
The correct answer is A. (76). The union of three sets is (30+34+36-8-10-6+0=76). If the centre is empty, keep the final addition as (0).
Exam Tip
तीन समुच्चयों का संघ (30+34+36-8-10-6+0=76) है। यदि केंद्र खाली हो तो अंतिम जोड़ (0) रखें।
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