Class 11 Mathematics - Straight Lines - Slope of a line and angle between two lines Expert Quiz

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रेखा का समीकरण \(4x-3y=15\) है। इस रेखा की ढाल क्या है?

The equation of a line is \(4x-3y=15\). What is the slope of this line?

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Correct Answer

A. \(\frac{4}{3}\)

Explanation

Simple Explanation

समीकरण को ढाल-अवरोध रूप में लिखें: \(4x-3y=15\Rightarrow y=\frac{4}{3}x-5\)। \(y=mx+c\) में \(x\) का गुणांक ढाल \(m\) होता है, इसलिए ढाल \(\frac{4}{3}\) है। \(\frac{3}{4}\) इसका परिमाणात्मक प्रतिलोम है, ढाल नहीं। परीक्षा-युक्ति: पहले समीकरण को \(y=mx+c\) के रूप में बदलें। / Rewrite the equation in slope-intercept form: \(4x-3y=15\Rightarrow y=\frac{4}{3}x-5\). In \(y=mx+c\), the coefficient of \(x\) is the slope \(m\), so the slope is \(\frac{4}{3}\). The value \(\frac{3}{4}\) is its reciprocal, not the slope. Exam tip: first isolate \(y\) and compare the equation with \(y=mx+c\).

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