\(\frac{3!+2!+1!}{0!}\) का मान क्या है?
What is the value of \(\frac{3!+2!+1!}{0!}\)?
Explanation opens after your attempt
B. 9
Simple Explanation
\(3!=6\), \(2!=2\) और \(1!=1\)। अतः अंश \(6+2+1=9\) है। साथ ही \(0!=1\), इसलिए \(\frac{9}{1}=9\)। विकल्प 8 तब मिल सकता है जब \(1!\) को गलती से 0 मान लिया जाए। परीक्षा टिप: \(0!=1\) और \(1!=1\) दोनों को हमेशा याद रखें। / \(3!=6\), \(2!=2\), and \(1!=1\). Therefore, the numerator is \(6+2+1=9\). Also, \(0!=1\), so \(\frac{9}{1}=9\). Option 8 may result from incorrectly taking \(1!\) as 0. Exam tip: Always remember that both \(0!\) and \(1!\) are equal to 1.
Login to save your score, XP, coins and progress.
QR scan karne par isi question ka correct answer aur explanation khula hua milega.
Open answer link