समुच्चय \(A={x\in \mathbb{R}:x^2+1=2x}\) किसके बराबर है?
Which set is \(A={x\in \mathbb{R}:x^2+1=2x}\) equal to?
Explanation opens after your attempt
A. ({1})
Concept
Rewrite the equation as \(x^2-2x+1=0\).
Why this answer is correct
This is ((x-1)2=0), so (x=1).
Exam Tip
A repeated solution is written only once in a set. चरण 1: समीकरण को \(x^2-2x+1=0\) लिखें। चरण 2: यह ((x-1)2=0) है, इसलिए (x=1)। चरण 3: दोहराया हल समुच्चय में एक ही बार लिखा जाता है।
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