समुच्चय \(A={x\in \mathbb{R}:x^2+1=2x}\) किसके बराबर है?

Which set is \(A={x\in \mathbb{R}:x^2+1=2x}\) equal to?

Explanation opens after your attempt
Correct Answer

A. ({1})

Step 1

Concept

Rewrite the equation as \(x^2-2x+1=0\).

Step 2

Why this answer is correct

This is ((x-1)2=0), so (x=1).

Step 3

Exam Tip

A repeated solution is written only once in a set. चरण 1: समीकरण को \(x^2-2x+1=0\) लिखें। चरण 2: यह ((x-1)2=0) है, इसलिए (x=1)। चरण 3: दोहराया हल समुच्चय में एक ही बार लिखा जाता है।

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Mathematics Answer, Explanation and Revision Hints

समुच्चय \(A={x\in \mathbb{R}:x^2+1=2x}\) किसके बराबर है? / Which set is \(A={x\in \mathbb{R}:x^2+1=2x}\) equal to?

Correct Answer: A. ({1}). Explanation: चरण 1: समीकरण को \(x^2-2x+1=0\) लिखें। चरण 2: यह ((x-1)2=0) है, इसलिए (x=1)। चरण 3: दोहराया हल समुच्चय में एक ही बार लिखा जाता है। / Step 1: Rewrite the equation as \(x^2-2x+1=0\). Step 2: This is ((x-1)2=0), so (x=1). Step 3: A repeated solution is written only once in a set.

Which concept should I revise for this Mathematics MCQ?

Rewrite the equation as \(x^2-2x+1=0\).

What exam hint can help solve this Mathematics question?

A repeated solution is written only once in a set. चरण 1: समीकरण को \(x^2-2x+1=0\) लिखें। चरण 2: यह ((x-1)2=0) है, इसलिए (x=1)। चरण 3: दोहराया हल समुच्चय में एक ही बार लिखा जाता है।