असमानता \(\frac{2x-1}{3}\geq 5\) का हल कौन सा है?
Which is the solution of \(\frac{2x-1}{3}\geq 5\)?
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Correct Answer
A. \(x\geq 8\)
Concept
From \(2x-1\geq 15\), we get \(2x\geq 16\) and \(x\geq 8\). Removing a positive denominator keeps the sign unchanged.
Why this answer is correct
The correct answer is A. \(x\geq 8\). From \(2x-1\geq 15\), we get \(2x\geq 16\) and \(x\geq 8\). Removing a positive denominator keeps the sign unchanged.
Exam Tip
\(2x-1\geq 15\) से \(2x\geq 16\) और \(x\geq 8\) मिलता है। सकारात्मक हर हटाने पर चिन्ह वही रहता है।
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