\(समुच्चय (E_1={x \in \mathbb{N}:x\) विषम है और \(x\leq 11}) का रोस्टर रूप कौन सा है\)?
\(Which is the roster form of (E_1={x \in \mathbb{N}:x\) is odd and \(x\leq 11})\)?
Explanation opens after your attempt
B. ({1,3,5,7,9,11})
Concept
Write odd natural numbers up to (11).
Why this answer is correct
Since the condition is \(\leq 11\), (11) is included.
Exam Tip
When equality is included in the boundary, check the endpoint. चरण 1: (11) तक विषम प्राकृतिक संख्याएँ लिखें। चरण 2: \(\leq 11\) होने से (11) शामिल होगा। चरण 3: सीमा में बराबरी हो तो अंतिम मान को अवश्य जाँचें।
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