असमानता \(2y-x\le 6\) को (y) के रूप में लिखने पर कौन-सा रूप सही है?
Which form is correct when \(2y-x\le 6\) is written in terms of (y)?
Explanation opens after your attempt
Correct Answer
A. \(y\le \frac{x+6}{2}\)
Concept
Adding (x) gives \(2y\le x+6\). Hence \(y\le \frac{x+6}{2}\) is correct.
Why this answer is correct
The correct answer is A. \(y\le \frac{x+6}{2}\). Adding (x) gives \(2y\le x+6\). Hence \(y\le \frac{x+6}{2}\) is correct.
Exam Tip
\(2y-x\le 6\) में (x) जोड़ने पर \(2y\le x+6\) मिलता है। इसलिए \(y\le \frac{x+6}{2}\) सही है।
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