ग्राफ \(y=x^2-6x+11\) का शीर्ष बिंदु कौन सा है?
What is the vertex of the graph \(y=x^2-6x+11\)?
Explanation opens after your attempt
A. ( \left\(3,2\right\) )
Concept
Completing the square gives (y=(x-3)2+2). Therefore the vertex is (\left\(3,2\right\)).
Why this answer is correct
The correct answer is A. ( \left\(3,2\right\) ). Completing the square gives (y=(x-3)2+2). Therefore the vertex is (\left\(3,2\right\)).
Exam Tip
पूर्ण वर्ग बनाने पर (y=(x-3)2+2) मिलता है। इसलिए शीर्ष (\left\(3,2\right\)) है।
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