व्यवस्था (x+y<5), (x+y>5), \(x\ge0\), \(y\ge0\) का हल क्षेत्र क्या होगा?
What is the solution region of (x+y<5), (x+y>5), \(x\ge0\), \(y\ge0\)?
Explanation opens after your attempt
Correct Answer
C. रिक्त समुच्चयEmpty set
Concept
It is impossible for (x+y) to be both less than and greater than (5) at the same time. Opposite inequalities can make the solution empty.
Why this answer is correct
The correct answer is C. रिक्त समुच्चय / Empty set. It is impossible for (x+y) to be both less than and greater than (5) at the same time. Opposite inequalities can make the solution empty.
Exam Tip
एक ही समय में (x+y) का (5) से कम और अधिक होना असंभव है। विरोधी असमानताएं मिलने पर हल रिक्त हो सकता है।
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