फलन (f(x)=\frac{1}{x+4}+6) का परिसर कौन सा है?

What is the range of (f(x)=\frac{1}{x+4}+6)?

Explanation opens after your attempt
Correct Answer

A. (\(-\infty,6\)\cup\(6,\infty\))

Step 1

Concept

\(\frac{1}{x+4}\) is never (0). Therefore (f(x)) is never (6).

Step 2

Why this answer is correct

The correct answer is A. (\(-\infty,6\)\cup\(6,\infty\)). \(\frac{1}{x+4}\) is never (0). Therefore (f(x)) is never (6).

Step 3

Exam Tip

\(\frac{1}{x+4}\) कभी (0) नहीं होता। इसलिए (f(x)) कभी (6) नहीं होता।

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Mathematics Answer, Explanation and Revision Hints

फलन (f(x)=\frac{1}{x+4}+6) का परिसर कौन सा है? / What is the range of (f(x)=\frac{1}{x+4}+6)?

Correct Answer: A. (\(-\infty,6\)\cup\(6,\infty\)). Explanation: \(\frac{1}{x+4}\) कभी (0) नहीं होता। इसलिए (f(x)) कभी (6) नहीं होता। / \(\frac{1}{x+4}\) is never (0). Therefore (f(x)) is never (6).

Which concept should I revise for this Mathematics MCQ?

\(\frac{1}{x+4}\) is never (0). Therefore (f(x)) is never (6).

What exam hint can help solve this Mathematics question?

\(\frac{1}{x+4}\) कभी (0) नहीं होता। इसलिए (f(x)) कभी (6) नहीं होता।