असमीका \(\frac{5-2x}{7}<-1\) का अंतराल रूप क्या है?
What is the interval form of \(\frac{5-2x}{7}<-1\)?
Explanation opens after your attempt
B. (\(6,\infty\))
Concept
(5-2x<-7) gives (-2x<-12), so (x>6). Use an open endpoint for a strict inequality.
Why this answer is correct
The correct answer is B. (\(6,\infty\)). (5-2x<-7) gives (-2x<-12), so (x>6). Use an open endpoint for a strict inequality.
Exam Tip
(5-2x<-7) से (-2x<-12), इसलिए (x>6)। परीक्षा में सख्त असमीका के लिए खुला सिरा लगाएं।
Login to save your score, XP, coins and progress.
