असमानता \(4-3x\le -8\) का सही हल कौन सा है?

What is the correct solution of \(4-3x\le -8\)?

Explanation opens after your attempt
Correct Answer

A. \(x\ge 4\)

Step 1

Concept

From \(4-3x\le -8\), we get \(-3x\le -12\), and dividing by (-3) gives \(x\ge 4\). Division by a negative reverses the sign.

Step 2

Why this answer is correct

The correct answer is A. \(x\ge 4\). From \(4-3x\le -8\), we get \(-3x\le -12\), and dividing by (-3) gives \(x\ge 4\). Division by a negative reverses the sign.

Step 3

Exam Tip

\(4-3x\le -8\) से \(-3x\le -12\) और (-3) से भाग देने पर \(x\ge 4\) मिलता है। ऋणात्मक भाग में चिन्ह उलटता है।

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Mathematics Answer, Explanation and Revision Hints

असमानता \(4-3x\le -8\) का सही हल कौन सा है? / What is the correct solution of \(4-3x\le -8\)?

Correct Answer: A. \(x\ge 4\). Explanation: \(4-3x\le -8\) से \(-3x\le -12\) और (-3) से भाग देने पर \(x\ge 4\) मिलता है। ऋणात्मक भाग में चिन्ह उलटता है। / From \(4-3x\le -8\), we get \(-3x\le -12\), and dividing by (-3) gives \(x\ge 4\). Division by a negative reverses the sign.

Which concept should I revise for this Mathematics MCQ?

From \(4-3x\le -8\), we get \(-3x\le -12\), and dividing by (-3) gives \(x\ge 4\). Division by a negative reverses the sign.

What exam hint can help solve this Mathematics question?

\(4-3x\le -8\) से \(-3x\le -12\) और (-3) से भाग देने पर \(x\ge 4\) मिलता है। ऋणात्मक भाग में चिन्ह उलटता है।