असमानता \(4-3x\le -8\) का सही हल कौन सा है?
What is the correct solution of \(4-3x\le -8\)?
Explanation opens after your attempt
A. \(x\ge 4\)
Concept
From \(4-3x\le -8\), we get \(-3x\le -12\), and dividing by (-3) gives \(x\ge 4\). Division by a negative reverses the sign.
Why this answer is correct
The correct answer is A. \(x\ge 4\). From \(4-3x\le -8\), we get \(-3x\le -12\), and dividing by (-3) gives \(x\ge 4\). Division by a negative reverses the sign.
Exam Tip
\(4-3x\le -8\) से \(-3x\le -12\) और (-3) से भाग देने पर \(x\ge 4\) मिलता है। ऋणात्मक भाग में चिन्ह उलटता है।
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